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5x^2=30-65x
We move all terms to the left:
5x^2-(30-65x)=0
We add all the numbers together, and all the variables
5x^2-(-65x+30)=0
We get rid of parentheses
5x^2+65x-30=0
a = 5; b = 65; c = -30;
Δ = b2-4ac
Δ = 652-4·5·(-30)
Δ = 4825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4825}=\sqrt{25*193}=\sqrt{25}*\sqrt{193}=5\sqrt{193}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-5\sqrt{193}}{2*5}=\frac{-65-5\sqrt{193}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+5\sqrt{193}}{2*5}=\frac{-65+5\sqrt{193}}{10} $
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